Hello,
I am having trouble making my model work for elastic-plastic material behaviour. Ultimately I want to make an analysis for a coupling. To do so I made a very basic model of a bar with a force on one end and a fixed bearing on the other end. All models work fine with Hooke's law and the given examples work also with von Mises's law. I attached the project file; maybe there is something wrong with my boundary condtions?
Thank you in advance!
Nonlinear strength (Von Mises)
Moderatoren: ccad, mz15, auroraIco, Lehrstuhl
Nonlinear strength (Von Mises)
- Dateianhänge
-
- Balken3.zip
- (1.05 MiB) 110-mal heruntergeladen
Re: Nonlinear strength (Von Mises)
Hallo Erdnuss,
Unfortunately, the material definition is missing in the attached project.
What material did you want to use? If you have created one yourself, can you provide it?
Best regards
ClaKle
Unfortunately, the material definition is missing in the attached project.
What material did you want to use? If you have created one yourself, can you provide it?
Best regards
ClaKle
Re: Nonlinear strength (Von Mises)
Hello ClaKle,
I tried it in the beginning for testing reasons with "Engineering Steel". In the end I want to use Aluminum for which I have a given flow curve. Unfortunately it didn't work with either of them.
Best regards,
Erdnuss
I tried it in the beginning for testing reasons with "Engineering Steel". In the end I want to use Aluminum for which I have a given flow curve. Unfortunately it didn't work with either of them.
Best regards,
Erdnuss
Re: Nonlinear strength (Von Mises)
Hallo Erdnuss,
first of all it is of course important that all material data is available. Therefore check in any case whether the flow curve for the Wehmann model is there.
I also took a closer look at your model. You used linear tetrahedra. In the Wehmann model, the nonlinear solver only works for quadratic tetrahedra. That's how it works
Best regards,
ClaKle
first of all it is of course important that all material data is available. Therefore check in any case whether the flow curve for the Wehmann model is there.
I also took a closer look at your model. You used linear tetrahedra. In the Wehmann model, the nonlinear solver only works for quadratic tetrahedra. That's how it works
Best regards,
ClaKle
Re: Nonlinear strength (Von Mises)
Hi ClaKle,
thanks a lot! I wasn't aware that I had to use the quadratic tetrahedra.. although it's logical.
Best regards,
Erdnuss
thanks a lot! I wasn't aware that I had to use the quadratic tetrahedra.. although it's logical.
Best regards,
Erdnuss